Browsing through the last week entries of my subscriptions, I stumbled across an interesting post entitled
"How to write Iterators really REALLY fast". It is about simulating the
yield functionality available in C# iterator blocks as of .NET 2.0 - as you might have guessed: it allows to write iterators really fast. =)
The author presents an example featuring a utility class
Yielder, which provides the same ease-of-use completely without pre-compilers and keyword overrides/additions. However, the implementation details were not published with it - but promised for next week (as of now 'this' week). Feeling eager how this can be done, I tried implementing the interface based on the descriptions in the text and the mentioned examples (one repeated here for convenience):
public Iterator iterator() {
return new Yielder() {
public void yieldNextCore() {
for (Object nextItem : coll) {
if (pred.evaluate(nextItem)) {
yieldReturn(nextItem);
}
}
}
};
}
However, it turned out that the task was not as easy as I thought. Actually, it took me over one hour to write one and I didn't succeed in making it as efficient as a true "yield".
Probably, the author will soon present a smart solution to the two challenges I encountered:
1. How to create more than one Iterator from a single Yielder instance?Obviously,
yieldReturn is a method of the
Yielder class, so it is not (automatically) aware of the a specific
Iterator instance. Therefore, I moved the method (along with a
yieldBreak equivalent) to an interface which will be passed to the iterator-block (
yieldNextCore).
2. How to avoid multiple iterations without an additional collection as storage?Maybe my intuition is wrong, but the
Next in
yieldNextCore implies to me that the method will be called repeatedly. Probably until it exits after a
yieldBreak call or without one to
yieldReturn. Hence, in the example above it would be the number of elements the predicate
pred evaluates to
true. Taking the worst case: One call for each of the
n elements in the collection
coll. Ergo the time scale rises from O(n) to O(n^2)!
Anyway, I might be wrong and it is only called once. Thus however, an element passed to
yieldReturn has be stored until the corresponding
Iterator.next call releases it. In a single threaded environment, the means
all of the (predicated) elements since there is no way to suspend the for-loop. This may be practicable for iterations over a few elements. But again, the worst cast the complexity rises from O(n) to O(n^2) - this time in memory consumption!
As a result, the only possible implementation idea I got was utilizing a dedicated thread to execute the iterator-block (
yieldNextCore). This can block the iteration while the iterators' method can return. However, it turned out one thread is not enough, since it could "wait forever", if the iteration is not completed. Another had to monitor a weak reference to it. But again, the the problem is that the loop will always be executed, which leads to O(n) even if the iteration is not continued after retrieving the first element.
Programming in Scala is a lot of fun for me, but I really love 
